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How does the Fast Lane create a zero in the transfer function?

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I am analyzing the effect of the Fast Lane through an operational amplifier circuit. It seems as though the Fast Lane creates a zero, but I am not entirely sure about this.

If the output impedance of the operational amplifier is \$0 \Omega\$, I believe no zero is created. However, since in practice the op-amp has some finite output impedance, a zero does appear. Unfortunately, I don't fully understand which circuit elements contribute to the formation of the zero, it seems to me that the op-amp's output impedance might also play a role.

I have conducted a FACT analysis (I’m still learning the method), but I get stuck when it comes to determining the zero.

Could someone help me with this?

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